In a TV pictgure tubeelectrons re ejected from the cathode with negligible speed and reach a velocity of `5x10^6` m/s in travelling one centimeter. Assuming straight line motion, find the constant force exerted on the electron. The mass of the electron is `9.1xx10^-31` kg.

Explanation

To solve the problem step by step, we will use the equations of motion and Newton's second law of motion.

### Step 1: Identify the given values
- Initial velocity (u) = 0 m/s (negligible speed)
- Final velocity (v) = \(5 \times 10^6\) m/s
- Distance traveled (s) = 1 cm = \(1 \times 10^{-2}\) m
- Mass of the electron (m) = \(9.1 \times 10^{-31}\) kg

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