A block of mass 0.2 kg is suspended from the ceiling by a light string. A second block of mass 0.3 kg is suspended from the first block through another string. Find the tensions in the two strings. Take `g=10 m/s^2`.

Explanation

To solve the problem of finding the tensions in the two strings suspending the blocks, we can follow these steps:

### Step 1: Identify the Forces Acting on the Second Block (0.3 kg)
For the second block (mass = 0.3 kg):
- The weight of the block acts downward: \( W_2 = m_2 \cdot g = 0.3 \, \text{kg} \cdot 10 \, \text{m/s}^2 = 3 \, \text{N} \).
- The tension in the string connecting the second block to the first block acts upward: \( T_2 \).

Using Newton's second law (since the block is in equilibrium and not accelerating):
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