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A block of mass m slips on a rough horiz...

A block of mass m slips on a rough horizontal table under the action of horiozontal force applied to it. The coefficient of friction between the block and the table is `mu`. The table does not move on the floor. Find the total frictional force aplied by the floor on the legs of the table. Do you need the friction coefficient between the table and the floor or the mass of the table ?

Text Solution

Verified by Experts

Because the block slipa on the table, maxium frictioN/Al force acts on it.
From the free body diagram
R=mg`

`:. F-muR=0`
`rarr F=muR=mumg`
But the table is at ret so frictioN/Al force at the legs of the table is also `muR_1`. Let it be so from the free body diagram,
`f_0-muR=0`
`rarr f_0=muR=mumg`
Total frictioN/Al froce on table by floor is `mumg`
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