Find the magnitude of the linear acceleration of a particle moving in a circle of radius 10 cm with uniform speed completing the circle in 4s.

Options

A. `1.5pi^2`
B. `2.5pi^2`
C. `3.5pi^2`
D. `4.5pi^2`

Answer

B

Explanation

The distance covered in completing the circle is `2pir=2pixx10cm.` The linear speed is
`v=2pi r/t`
`=(2pixx10cm)/(4s)=5pi cm/s`.
Thelinear acceleration is
`=v^2/r=((5picm/s)^2)/(10cm)=2.5pi^2cm/s^2`
This acceleration is directed towards the centre of the circle.