Find the acceleration of a particle placed on the surface of the earth at the equator due to earth's rotation. The diameter of erth =12800 km andit takes 24 hour for the earth to comlete one revolution about its axis.

Answer

B, C

Explanation

Diameter of earth = 12800 km
Radius of earth `R=6400 km=64xx10^5` m
`T=24hr=24xx3600sec`
v=(2pir)/T`
`=(2xx3.14xx64xx10^5)/(24xx3600)`
`=465.185`
`a=v^2/R=((465.185)^2)/(64xx10^5)`
` 0.038m/sec^2`