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A block of mass 5.0 kg slides down an in...

A block of mass 5.0 kg slides down an incline of inclination `30^0` and length 10 m. The work done by the force of gravity (in joule) is

Text Solution

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The correct Answer is:
B, D
`M=5 kg, theta=30^0,S=10m, F=mg`
so, workdone by the force of gravity,
`omega=mgh=5xx9.8xx5`
`=245J`
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Knowledge Check

  • A block of mas m begins to slide down on an inclined plane of inclination theta . The force of friction will be

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