A block o fmass 250 is g is kept on a vertical spring of spring constant 100 N/m fixed from below. The spring is now compressed to have length 10 cm shorter than its natural length and the system is released from this position. How high does the block rise? take `g=10 m/s^2`.

Answer

B, C

Explanation

`m=250g=0.25kg, k=100N/m`
`x=10cm`
`=0.1m`
`g=10 m/sec^2,h=?`
Applying law of energy
`1/2kx^2=mg`
`rarr h=1/2((kx^2)/(mg))`
`=(100xx0.01)/(2x(0.250)xx10)`
0.2m=20cm`