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All the particles of a body are situated...

All the particles of a body are situated at a distance R from the origin. The distance of the centre of mass of the body from the origin is

A

`=R`

B

`leR`

C

`gtR`

D

`geR`

Text Solution

AI Generated Solution

The correct Answer is:
To find the distance of the center of mass of a body where all particles are situated at a distance \( R \) from the origin, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the System**: - All particles of the body are at a distance \( R \) from the origin. This means that each particle is located on a sphere of radius \( R \). 2. **Assuming Particle Distribution**: - For simplicity, let's assume that the particles are evenly distributed over the surface of a sphere of radius \( R \). This means that half of the particles are on the x-axis and half are on the y-axis. 3. **Calculating the Center of Mass**: - The center of mass (COM) is calculated using the formula: \[ \text{COM} = \frac{\sum m_i \vec{r_i}}{\sum m_i} \] - If we assume uniform mass distribution and equal mass for each particle, the center of mass will be influenced by the symmetry of the arrangement. 4. **Finding the Coordinates**: - If we consider two particles at positions \( (R, 0) \) and \( (0, R) \), the coordinates of the center of mass in the x and y directions can be calculated as: \[ x_{cm} = \frac{R + 0}{2} = \frac{R}{2} \] \[ y_{cm} = \frac{0 + R}{2} = \frac{R}{2} \] 5. **Distance from the Origin**: - The distance \( h \) of the center of mass from the origin can be calculated using the Pythagorean theorem: \[ h = \sqrt{x_{cm}^2 + y_{cm}^2} = \sqrt{\left(\frac{R}{2}\right)^2 + \left(\frac{R}{2}\right)^2} \] - Simplifying this gives: \[ h = \sqrt{\frac{R^2}{4} + \frac{R^2}{4}} = \sqrt{\frac{2R^2}{4}} = \sqrt{\frac{R^2}{2}} = \frac{R}{\sqrt{2}} \] 6. **Conclusion**: - Therefore, the distance of the center of mass of the body from the origin is: \[ h = \frac{R}{\sqrt{2}} \] ### Final Answer: The distance of the center of mass of the body from the origin is \( \frac{R}{\sqrt{2}} \).
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