`7x+3/x=35 3/5`

Find the value of x , (x - 3)/5 + (x - 4)/7 = 6 - (2x - 1)/(35)

Solve the quadratic equation by factorisation: 3((7x+1)/(5x-3))-4((5x-3)/(7x+1))=11 x != 3//5, x != 1//7

Add: 7x, -3x, 5x, -x, -2x

Each of four particles moves along an x axis. Their coordinates (in meters) as function of time (in seconds) are given by Particle 1:x(t) =3.5 -2.7t^(3) Particle :2 x(t)=3.5+2.7 t^(3) particle 3: x(t) =3.5+2.7 t^(2) particle 4: x(t)=3.5-3.4 t -2.7 t^(2) Which of these particles have constant acceleration ?

If the sum to infinity of the series 1 + 4x + 7x^2 + 10x^3 +............. is 35/16 then x= (A) 1/5 (B) 2/5 (C) 3/7 (D)1/7

If the sum to infinity of the series 1 + 4x + 7x^2 + 10x^3 +............. is 35/16 then x= (A) 1/5 (B) 2/5 (C) 3/7 (D) 1/7

If the sum to infinity of the series 1 + 4x + 7x^2 + 10x^3 +............. is 35/16 then x= (A) 1/5 (B) 2/5 (C) 3/7 (D) 1/7

If x= (3)/(4.8) + (3.5)/(4.8.12)+ (3.5.7)/(4.812.16) + …., then 2x^2+5x=

The equation of the line joining the point (3,5) to the point of intersection of the lines 4x+y-1=0 and 7x-3y-35=0 is equidistant from the points (0,0) and (8,34) .

The equation of the line joining the point (3,5) to the point of intersection of the lines 4x+y-1=0 and 7x-3y-35=0 is equidistant from the points (0,0) and (8,34) .