Let a = 6, b = 3 and `cos (A -B) = (4)/(5)`
Angle C is equal to

Let a = 6, b = 3 and cos (A -B) = (4)/(5) Value of sin C is equal to

Let a = 6, b = 3 and cos (A -B) = (4)/(5) Value of sin A is equal to

Let a = 6, b = 3 and cos (A -B) = (4)/(5) Value of sin A is equal to

Let a = 6, b = 3 and cos (A -B) = (4)/(5) Value of sin A is equal to

Let a = 6, b = 3 and cos (A -B) = (4)/(5) Value of sin A is equal to

Let a = 6, b = 3 and cos (A -B) = (4)/(5) Area (in sq. units) of the triangle is equal to

Let a = 6, b = 3 and cos (A -B) = (4)/(5) Area (in sq. units) of the triangle is equal to

Let a = 6, b = 3 and cos (A -B) = (4)/(5) Area (in sq. units) of the triangle is equal to

Let a = 6, b = 3 and cos (A -B) = (4)/(5) Area (in sq. units) of the triangle is equal to

Let a,b, c are the sides opposite to angles A, B , C respectively in a Delta ABC tan""(A-B)/(2)=(a-b)/(a+b)cot ""C/2 and (a)/(sin A)=(b)/(sin B) =(c)/(sin C), If a=6,b=3 and cos (A-B) =4/5 Angle C is equal to