Two particles A and B of masses 1 kg and 2 kg respectively are kept 1 m apart and are released to move under mutual attraction. Find The speed A when that of B is 3.6 cm/hr. What is the separation between the particles at this instant?

Explanation

To solve the problem, we will follow these steps:

### Step 1: Understand the system
We have two particles A and B with masses \( m_A = 1 \, \text{kg} \) and \( m_B = 2 \, \text{kg} \) respectively, initially separated by a distance of \( r_0 = 1 \, \text{m} \). They are released to move under their mutual gravitational attraction.

### Step 2: Apply conservation of momentum
Since the system is isolated and no external forces are acting on it, the total momentum of the system must be conserved. Initially, both particles are at rest, so the initial momentum is zero.

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