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Find the height over the eart's surface ...

Find the height over the eart's surface at which the weight of a body becomes half of its alue t the surface.

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The correct Answer is:
A, B, D

Let the height be h
`:. (1/2)(GM)/R^2=(GM)/((R+h)^2)`
or `2R^2=(R+h)^2`
or `sqrt2R=R+h`
`h=(sqrt2-1)R`
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