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What is the acceleration due to gravity on the top of Mount Everest? Mount Everest is the highest mountain peak o het workd at the height of 8848 m. The value at see level is `9.80 ms^-2`.

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The correct Answer is:
B
Let g be the acceleration due to gravity on mount everest
`g'=g(1-(2h)/R)`
`=9.8(1-1796/6400000)`
`.9.8(1-0.00276)`
`=9.0(0.99724)`
`=9.773m/s^2`
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