A paricle of mass 200 g executes a simpl...

A paricle of mass `200 g` executes a simple harmonic motion. The restorting force is provided by a spring of spring constant `80 N//m`. Find the time period.

0.31 s

0.21 s

0.11 s

0.25 s

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Verified by Experts

The correct Answer is:

The time period is
`T=2pi sqrt(m/k)`
`=2pi(sqrt(200x10^-3kg)/(80Nm^-1))`
`2pix0.05s=0.31s`

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