Home
Class 11
PHYSICS
A particle executes a simple harmonic mo...

A particle executes a simple harmonic motion of time period T. Find the time taken by the particle to go directly from its mean position to half the amplitude.

Text Solution

AI Generated Solution

To solve the problem of finding the time taken by a particle executing simple harmonic motion (SHM) to move from its mean position to half the amplitude, we can follow these steps: ### Step 1: Understand the Motion In simple harmonic motion, the displacement \( x \) of the particle from the mean position can be described by the equation: \[ x(t) = A \sin(\omega t) \] where: - \( A \) is the amplitude, - \( \omega \) is the angular frequency, given by \( \omega = \frac{2\pi}{T} \) (with \( T \) being the time period). ...
Promotional Banner

Topper's Solved these Questions

  • SIMPLE HARMONIC MOTION

    HC VERMA|Exercise Short Answer|13 Videos
  • SIMPLE HARMONIC MOTION

    HC VERMA|Exercise Objective 1|21 Videos
  • SIMPLE HARMONIC MOTION

    HC VERMA|Exercise Exercises|58 Videos
  • ROTATIONAL MECHANICS

    HC VERMA|Exercise Exercises|86 Videos
  • SOME MECHANICAL PROPERTIES OF MATTER

    HC VERMA|Exercise Exercises|32 Videos

Similar Questions

Explore conceptually related problems

A particle executes SHM with a time period of 4 s . Find the time taken by the particle to go directly from its mean position to half of its amplitude.

A particle executes SHM with a time period of 12s. Find the time taken by the particle to go directly from its mean position to half of its amplitude.

A particle executing a simple harmonic motion has a period of 6 s. The time taken by the particle to move from the mean position to half the amplitude, starting from the mean position is

A particle executes S.H.M with time period 12 s. The time taken by the particle to go directly from its mean position to half its amplitude.

A particle executes S.H.M. with a time period of 3s. The time taken by the particle to go directly from its mean position to half of its amplitude is-

A particle executes SHM with a time period of 4 s . Find the time taken by the particle to go from its mean position to half of its amplitude . Assume motion of particle to start from mean position.

A particle of mass 2 kg executing SHM has amplitude 10 cm and time period 1s. Find (a) the angular frequency (b) the maximum speed (c ) the maxmum acceleration (d) the maximum restoring force ( e) the speed when the displacement from the mean position is 8 cm (f) the speed after (1)/(12)s the particle was at the extreme position (g) the time taken by the particle to go directly from its mean position to half the amplitude (h) the time taken by the particle to go directly from its extreme position to half the amplitude.

A particle undergoes simple harmonic motion having time period T. The time taken in 3/8th oscillation is

HC VERMA-SIMPLE HARMONIC MOTION-Worked Out Examples
  1. A block of mass 5 kg executes simple harmonic motion under the restori...

    Text Solution

    |

  2. A particle executing simple harmonic motion has angular frequency 6.28...

    Text Solution

    |

  3. A particle executes a simple harmonic motion of time period T. Find th...

    Text Solution

    |

  4. A block of mass m hangs from a vertical spring of spring constant k. I...

    Text Solution

    |

  5. A particle suspended from a vetical spring oscillastes 10 times per s...

    Text Solution

    |

  6. The pulley shown in figure has a moment of inertias I about its xis an...

    Text Solution

    |

  7. The friction coeficeint betweenteh tow blocks shown in figure is mu an...

    Text Solution

    |

  8. The left block in filgure collides inelastically with the right block ...

    Text Solution

    |

  9. Describe the motion of the mass m shown in figure. The walls and the b...

    Text Solution

    |

  10. A block of mass m is suspended from the ceiling of a stationary standi...

    Text Solution

    |

  11. The spring as shown in figure is kept in a stretched position with ext...

    Text Solution

    |

  12. Asume that as narrow tunnel is dug between two diametricaly opposite p...

    Text Solution

    |

  13. A simple pendulum of length 40 cm oscillates with an angular amplitude...

    Text Solution

    |

  14. A simple pendulum having a bob of mass m undergoes smasll oscillastion...

    Text Solution

    |

  15. A simple pendulum is taken at a place where its separation from the ea...

    Text Solution

    |

  16. A simple pendulum is suspnded from the ceilignof a car accelerating un...

    Text Solution

    |

  17. A uniform meter stickis suspended through a small pin hole at the 10 c...

    Text Solution

    |

  18. The moment of inertia of the disc used in a torsional pendulum about t...

    Text Solution

    |

  19. A uniform rod of mass m and length l is suspended through a light wire...

    Text Solution

    |

  20. A particle is subjected to two simple harmonic motions x1=A1 sinomeg...

    Text Solution

    |