A beaker of circular ceross sectionof radius 4 cm is filled with mercury up to a height of 10 cm. Find the force exerted by the mercury on the bottom of the beaker. The atmospheric pressure `=10^5Nm^-2`. Density of mercury `=13600 kgm^-3. Take g10ms^-2`

Explanation

The pressure at the surface
`=atmospheric pressure
`=10^5 Nm^-2`
`The pressure at the bottom
`=10^5Nm^-2+hrhog`
`=10^5Nm^-2+(0.1m)(13600kgm^-3)(10ms^-2)`
`=1.136xx10^5Nm^-2`
The force exerted by the mercury on the bottom
`=(1.136xx10^5Nm^I-2)xx(3.14xx0.04mxx0.04m)`
`=571N.