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A area of cross section of a large tank ...

A area of cross section of a large tank is `0.5m^2`. It has an opening near the bottom having area of cross section `1cm^2`. A load of 20 kg is applied on the water at the top. Find the velocity of the water coming out of the opening at the time when the height of water level is 50 cm above the bottom. Take `g=10ms^-2`

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To solve the problem step-by-step, we will use the principles of fluid mechanics, particularly Bernoulli's equation. ### Step 1: Identify the given data - Area of cross-section of the tank, \( A_t = 0.5 \, m^2 \) - Area of the opening, \( A_o = 1 \, cm^2 = 1 \times 10^{-4} \, m^2 \) - Load on the water, \( m = 20 \, kg \) - Height of water level, \( h = 50 \, cm = 0.5 \, m \) - Acceleration due to gravity, \( g = 10 \, m/s^2 \) ...
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