One end of a wire 2m long and 0.2 cm^2 in cross section is fixed in a ceilign and a load of 4.8 kg is attached to the free end. Find the extension of the wire. Young modulus of steel `=2.0xx10^11Nm^-2`. Take `g=10ms^-2`.

Explanation

To find the extension of the wire when a load is applied, we can use the formula for Young's modulus:

\[ Y = \frac{F/A}{\Delta L/L_0} \]

where:
- \( Y \) is the Young's modulus,
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