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Two waves are smultaneously passing thro...

Two waves are smultaneously passing through a string. The equation of the waves are given by
`y_1=A_1sink(x-vt)`
and `y_2=A_2sink(x=vt+x_0)`
where the wave number `k=6.28 cm^-1 and x_0=o1.50c. The ampitudes of `A_1=5.0mm and A_2=4.0mm. find the phase difference between the waves and the amplitude of the resulting wave.

Text Solution

Verified by Experts

The phase of the first wave is `k(x-vt)` and of the second is `k(x-vt+x_0)`
The phase difference is therefore,
`delta=k x_0=(6.28cm^-1)(1.50cm)=2pixx1.5=3pi`
The waves satisfy the condition of destructive interference. The amplitude of the resulting wave is given by
`|A_1-A_2|=5.0mm-4.0mm=1.0mm`.
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  14. A wave travelling on a string at a speed of 10 ms^-1 causes each parti...

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  15. A steel wire of length 64 cm weighs 5 g. If it is stretched by a force...

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  16. A string of length 20 cm and linear mass density 0.40 g cm^-1 is fixed...

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  17. A string of linear mass density 0.5 g cm^-1 and a total length 30 cm i...

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  19. A transverse wave described by y=(0.02m)sin[(1.0m^-1)x+(30s^-1)t] ...

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