A particle falls in a medium whose resistance is propotional to the square of the velocity of the particles. If the differential equation of the free fall is `(dv)/(dt) = g-kv^(2)` (k is constant) then

The differential equation whose solution is (y - b)^(2) = 4 k (x - a) (where b,a,k are constants ) is of

Solve the following differential equations.(2) d theta.dt=k(theta=theta_0) ,where k is a constant.

An object falling from rest in air is subject not only to the gravitational force but also to air resistance.Assume that the air resistance is proportional to the velocity with constant of proportionality as k>0, and acts in a direction opposite to motion (g=9.8(m)/(s^(2))) Then velocity cannot exceed.

If a particle with a = kv^(2) and initial velocity is u then velocity after S displacement. Here k is a constant

If a particle with a = kv^(2) and initial velocity is u then velocity after S displacement. Here k is a constant

An object falling from rest in air is subject not only to the gravitational force but also to air resistance. Assume that the air resistance is proportional to the velocity with constant of proportionality as k >0 , and acts in a direction opposite to motion (g=9. 8 m/(s^2))dot Then velocity cannot exceed.