[" 2) If the eqn of the locus of a point "],[" cquidistance from the point "(AE)/(2),B(a,b)],[(a_(2),b_(2))" is "(a_(1)-a_(2))x+(b_(1)-b_(2))y+c=0],[" Then "c=]

If the equation of the locus of a point equidistant from the points (a_(1), b_(1)) and (a_(2), b_(2)) is : (a_(1)-a_(2))x+(b_(1)-b_(2))y+c=0 , then c =

If the equation of the locus of a point equidistant from the points (a_(1),b_(1)) and (a_(2),b_(2)) is (a_(1)-a_(2))x+(b_(1)-b_(2))y+c=0 then the value of c is

If the equation of the locus of a point equidistant from the points (a_(1),b_(1)) and (a_(2),b_(2)) is (a-1-a_(2))x+(b_(1)-b_(2))y+c=0, then the value of c is

If the equation of the locus of a point equidistant from the points (a_(1),b_(1)) and (a_(2),b_(2)) is (a_(1)-a_(2))x+(b_(1)-b_(2))y+c=0 then the value of c'is:

If the equation of the locus of a point equi-distant from the points (a_(1), b_(1)) and (a_(2),b_(2)) is (a_(1)-a_(2))x+(b_(1)-b_(2))y+c=0 then the value of c is

Find the equation of locus of point equidistant from the points (a_(1)b_(1)) and (a_(2),b_(2)) .

Find the equation of locus of point equidistant from the points (a_(1)b_(1)) and (a_(2),b_(2)) .

If the equation of the locus of a point equidistant from the points ( a_ 1 , b _ 1 ) and ( a _ 2, b _ 2 ) is ( a _ 1- a _ 2 ) x + ( b _ 1 - b _ 2 ) y + c = 0 then the value of c is

If the points (a_(1),b_(1))m(a_(2),b_(2))" and " (a_(1)-a_(2),b_(2)-b_(2)) are collinear, then prove that a_(1)/a_(2)=b_(1)/b_(2)