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ABC to Figure 10.27. ABCD and EFGD are t...

ABC to Figure 10.27. ABCD and EFGD are two parallelograms and is the mid-point of side en Then, ar (DPO) = a(EPGD). P Figure 10.27

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In the figure ABCD and EFGD are two parallelograms and G is the mid-point of CD. Then ar(DPC) = 1/2 ar(EFGD)

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