[" If "(cos theta+i sin theta)(cos2 theta+i sin2 theta)...(cos n theta+i sin],[n theta)=1," then the value of "theta" is "]

If (cos theta + i sin theta)(cos 2 theta +i sin 2 theta ) …(cos n theta + i sin n theta)=1 then the value of theta is (m are integers)-

" (i) "(cos theta+sin theta)/(cos theta-sin theta)

If (cos theta+i sin theta) .(cos 2 theta+i sin 2 theta) ldots ldots(cos m theta+i sin m theta)=1 then the value of theta is

cos theta+sin theta=cos2 theta+sin2 theta

(cos theta + i sin theta) ^ (n) = cos n theta + i sin n theta

If ((1+cos theta+i sin theta)/(sin theta+i+i cos theta))^(4)=cos n theta+i sin n theta , then n=

(cos theta + sin theta )/( cos theta - sin theta )-(cos theta - sin theta )/( cos theta + sin theta ) =

Prove that ((1+cos theta+i sin theta)/(1+cos theta-i sin theta))^(n)=cos n theta+i sin n theta

(1+cos theta+i sin theta)^(10)+(1+cos theta-i sin theta)^(10)=