A nuclear explosion has taken place leading to increase in concentration of `C^(14)` in nearby areas. `C^(14)` concentration is `C_(1)` in nearby areas and `C_(2)` in areas far away. If the age of the fossil is determind to be `T_(1) and T_(2)` at the places respectively then

Carbon -14 used to determine the age of organic material. The procedure is absed on the formation of C^(14) by neutron capture iin the upper atmosphere. ._(7)N^(14)+._(0)n^(1) rarr ._(6)C^(14)+._(1)H^(1) C^(14) is absorbed by living organisms during photosynthesis. The C^(14) content is constant in living organism. Once the plant or animal dies, the uptake of carbon dioxide by it ceases and the level of C^(14) in the dead being falls due to the decay, which C^(14) undergoes. ._(6)C^(14)rarr ._(7)N^(14)+beta^(c-) The half - life period of C^(14) is 5770 year. The decay constant (lambda) can be calculated by using the following formuls : lambda=(0.693)/(t_(1//2)) The comparison of the beta^(c-) activity of the dead matter with that of the carbon still in circulation enables measurement of the period of the isolation of the material from the living cycle. The method, however, ceases to be accurate over periods longer than 30000 years. The proportion of C^(14) to C^(12) in living matter is 1:10^(12) . A nuclear explosion has taken place leading to an increase in the concentration of C^(14) in nearby areas. C^(14) concentration is C_(1) in nearby areas and C_(2) in areas far away. If the age of the fossil is determined to be T_(1) and T_(2) at the places , respectively, then

Carbon 14 is used to determine the age of organic material. The procerdure is based on the formation of .^(14)C by neutron capture in the upper atmosphere. ._(7)^(14)N + ._(0)^(1)n rarr ._(6)^(14)C + ._(1)n^(1) .^(14)C is abosorbed by living organisms during phostosythesis. The .^(14)C content is constant in living organisms once the plant or animal dies, the uptake of carbon dioxide by it ceases and the level of .^(14)C in the dead being, falls due to the decay which .^(14)C undergoes. ._(6)^(14)C rarr ._(7)^(14)C + beta^(-) The half-life period of .^(14)C is 5770 years. The decay constant (lambda) can be calculated by using the following formula lambda = (0.693)/(t_(1//2)) The comparison fo the beta^(-) activity fo the dead matter with that of the carbon still in circulation enables measurement of the period of the isolation the materail form the living cycle. The method however, ceases to be accurate ever periods longer than 30,000 years. The proportaion of .^(14)C to .^(12)C living matter is 1:10^(12) . A nulcear explosion has taken place leading to increases in conventration of ^(14)C in nearly areas. ^(14)C concentration is C_(1) in nearby areas and C_(2) in areas far away. If the age of the fossil is detemined to be T_(1) and T_(2) at the places respectively, then:

Find the area of the triangle whose vertices are : A(1,2,3), B(2,-1,4) and C(4,5,-1)

2IC1 rarr I_(2) + C1_(2) K_(C) = 0.14 Intitial concentration of IC1 is 0.6 M then equilibrium concentration of I_(2) is:

The fossil bone has a .^(14)C : .^(12)C ratio, which is [(1)/(16)] of that in a living animal bone. If the half -life of .^(14)C is 5730 years, then the age of the fossil bone is :