The refractive indices of silicate fint glass for wavelength 400 nm and 700 nm are 1.66 aned 1.61 respectively. Find the minimum angles of deviation of an equailateral prism made of this glass for light of wavelength 400 nm and 700 nm.

Explanation

To find the minimum angles of deviation for an equilateral prism made of silicate glass for light of wavelengths 400 nm and 700 nm, we can use the formula that relates the refractive index (μ) of the prism material, the angle of the prism (A), and the minimum angle of deviation (D_m):

\[ \mu = \frac{\sin\left(\frac{A + D_m}{2}\right)}{\sin\left(\frac{A}{2}\right)} \]

### Step 1: Identify the parameters
For an equilateral prism, the angle A is 60 degrees. We have two refractive indices:
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