A concave mirror of radius R is kept on a horizontal table. Water (refractive index =mu.) is poured into it up to a height h. Where should an object be placed so that its image is formed on itself ?

Answer

A, B, C

Explanation

Let the object be placed at a height x above the surface of the water.
The apparent positionn of the object with respect to mirror should be at the centre of curvature so that the image is formed at the same position
since, `(Real depth)/(Apparent depth)=1/mu`
(with respect to mirror)
now, x/(R-x)=1/mu`
`x=(R-h)/mu`