A light ray is incident at an angle of `45^@` with the normal to a `sqrt2` cm thick plate` (mu2.0)`. Find the shift in the path of the light as it emerges out from the plate.

Explanation

`v_1sin45^@=v_2sinr`

or `sinr=1/(2sqrt2)`
or cosr=sqrt7/(2sqrt2)`
or d[=t/(cosr)[sin(j-r)sinr]`
`=1/(2sqrt2)`
=`(sqrt2xx2sqrt2)/sqrt7`
` [(1xxsqrt7)/(sqrt2xx2sqrt20-1/sqrt2xx1/(2sqrt2)]`
`=4/(sqrt7xx4)[sqrt7-41]`
`=(sqrt7-1)/sqrt7`
`=0.63 cm