Find the angle of deviation suffered by the light ray shown in figure. The refractive index mu = for the prism material.

Answer

B

Explanation

`:.` is very small `4^@`
so, `deltaA(mu-1)`
`=4^@(1.5-1)=2^@`
`:.` A is very small
`:. R_1er_2` also very small
`:.A=r_1+r_2`
`sini=musinr_1`
`or i=mur_1`
sine=musinr_2`
e=mur_2`
`delta=(i-r_1)+(e-r_2)`
`=i+e-(r_1+r_2)`
`=mur_1-r_1+mur_2-r_2`
`=(r_1+r_2)(mu-1)`
`(r_1+r_2)(mu-1)`
`=A(mu-1)`