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The simple harmonic vibrations of two pa...

The simple harmonic vibrations of two particles are `y_(1)= 5sin (100t) and y_(2) = 4 cos (100t + pi/4)`. The phase difference between both particles is

A

`pi/4`

B

`pi/2`

C

`pi`

D

`(3pi)/4`

Text Solution

Verified by Experts

The correct Answer is:
D

`y_(1) = 5sin (100t)`
` and y_(2) = 4 cos (100 t + pi/4)`
` = 4 sin (pi/2 + (100 t + pi/4)`
` = 4 sin (100 t + (3pi)/4)`
Phase difference between these two vibrations .
`Deltaphi=phi_(2)-phi_(1)`
`or Deltaphi = (100 t + 3/4 pi) - (100t) = 3/4 pi`
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