The ion which is not tetrahedral in shape is

Options

A. `BF_(4)^(-)`
B. `NH_(4)^(+)`
C. `[Cu(NH_(3))_(4)]^(2+)`
D. `NiCI_(4)^(2-)`

Answer

C

Explanation

`BF_(4)^(-) , NH_(4)^(+), NiCL_(4)^(2-)` all are tetrahedral in shape but ` [Cu (NH_(3))_(4)]^(2)` is not tetrahedral but spuare planer.