Oxidation number if iodine in `IO_(3)^(-), IO_(4)^(-),KI and I_(2)` respectively are

Options

A. `-1,-1, 0, +1`
B. `+3, +5, +7, 0`
C. `+5,+7, -1,0`
D. `-1,-5,-1,0`

Answer

C

Explanation

Oxidation state of I in ` IO_(3)^(-) x + (-2)3= -1 Rightarrow x = +5`
Oxidation state of in `IO_(4)^(-)`
x+ (-2) 4 = -1 `Rightarrow ` x = -1
Oxidation state of I in KI
` + 1 + x = 0 Rightarrow x =-1`
Oxidation state of I in `I_(2) x =0`
Hence the oxidation number of iodine in `IO_(3)^(-) , IO_(4)^(-)` ,`KI and I_(2)` are respectively +5, + 7 -1 , and 0