A solution containing one mole per litre of each `Cu(NO_(3))_(2), AgNO_(3), Hg_(2)(NO_(3))_(2)` is being electrolysed by using inert electrodes. The values of standard electrode potentials in volts (reduction potentials) are
`Ag^(+)//Ag = +0.80 V, HG_(2)^(2+)//Hg = +0.79 V`
`Cu^(+)//Cu = +0.34 V, Mg^(2+)//Mg = -2.37 V`
With increasing valtage, the sequence of deposition of metals on the cathode will be

Options

A. Mg,Ag, Cu
B. Mg, Cu, Ag
C. Ag, Hg, Cu
D. Cu,Hg,Ag

Answer

C

Explanation

Higher the reduction potenial , more in the tendency to get reduced
` M^(n+) + ne^(-) to M(s)`
Hence , correct order is Ag, Hg, Cu