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The equation of the plane passing throug...

The equation of the plane passing through (3,2,-1) and normal tot the line (2,1,2) and (4,3,-1) is

A

x+2y-3z=12

B

2x-3y+z=11

C

2x+2y-3z=13

D

3x+2y-z=13

Text Solution

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The correct Answer is:
C
The DR's of the line joining the points (2,1,2) and (4,3,-1) is 4,-2,3-1,-1-2, i.e., 2,2,-3
`therefore` Equation of theh plane passing through (3,2,-1) and where DR's are 2,2,-3 is
`2(x-3)+2(y-2)-3(z+1)=0
`implies2x+2y-3z=13`
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