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For the Booleann function f(x(1),x(2),x(...

For the Booleann function `f(x_(1),x_(2),x_(3))=(x_(1)*x_(2))+x_(3),` value of `f(1,1,0)` is

A

0

B

1

C

`-1`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
Given `f(x_(1),x_(2),x_(3))=(x_(1)*x_(2))+x_(3)`
`thereforef(1,1,0)=(1*1)+0=1+0=1`
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