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The time period of a simple pendulum is ...

The time period of a simple pendulum is 2s. It its length is increased by 4 times, then its period becomes

A

16 s

B

12 s

C

8 s

D

4 s

Text Solution

Verified by Experts

The correct Answer is:
D
As, `Tpropsqrt(l)implies(T_(1))/(T_(2))=sqrt((l_(1))/(l_(2)))`
`implies(2)/(T_(2))=sqrt((l)/(4l))impliesT_(2)=4s`
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