A ray of light is incident at the glass-water interface at an angle `i` it emerges finnaly parallel to the surface of water, then the value of `mu_(g)` would be

Options

A. (4/3)sin i
B. 1/sin i
C. `4//3`
D. 1

Answer

B

Explanation

For glass-water interface
`._(g)mu_(w)=(sini)/(sinr)`
For water-air interface
`_(w)mu_(a)=(sinr)/(sin90^(@))`
`implies._(g)mu_(w)xx._(w)mu_(a)=(sini)/(sinr)xx(sinr)/(sin90^(@))`
`=sini`
or `(mu_(w))/(mu_(g))xx(mu_(a))/(mu_(w))=sin i impliesmu_(g)=(1)/(sini)`