The radius of a planet is a. satelite revolves around it in a circle of radius x with angular velocity `omega`. The acceleration due to the gravity on planet's surface is

Options

A. `(omega^(2)x^(3))/(a^(2))`
B. `(2omega^(2)x^(3))/(3a^(2))`
C. `(omega^(2)x^(2))/(a)`
D. `(omega^(2)x^(4))/(2a^(3))`

Answer

A

Explanation

`(GM m)/(x^(2))=momega^(2)ximpliesGM=omega^(2)x^(3)`
`ga^(2)=omega^(2)x^(3)" "[because(Gm^(2))/(a^(2))=g]`
`impliesg=(omega^(2)x^(3))/(a^(2))`