Voltmeters `V_(1)` and `V_(2)` are connected in series across a `D.C.` line `V_(1)` reads 80 volts and has a per volt resistance of `200 ohms`, `V_(2)` has a total resistance of 32 kilo ohms.
The line voltage is

Options

A. 120 V
B. 160 V
C. 220 V
D. 240 V

Answer

D

Explanation

`R_(1)=80xx200=16000Omega=16kOmega`
current through `V_(1) and V_(2)` is same
`l_(2)=(80)/(16xx10^(3))=5xx10^(-3)A`
So, potential difference across `V_(2)` is `V_(2)=5xx10^(-3)xx32xx10^(3)=160V`
Hence, line voltage`=V_(1)+V_(2)`
`=80+160=240V`