A deuteron of kinetic energy 100 keV is describing a circular motion in a cyclotron having orbit of radius 0.5 m, in a plane perpendicular to describes circular orbit in the cyclotron of radius 0.5 m in the sae plane with the same magnetic field is

Options

A. 200 keV
B. 50 keV
C. 100 keV
D. 25 keV

Answer

A

Explanation

In this case magnetic force provides necessary centripetal force
i.e., `qvb=(mv^(2))/(r)`
Radius of path `r=(mv)/(Bq)=(sqrt(2mE))/(qB)`
`r=(sqrt(2mE))/(Bq)=(sqrt(2m_(1)E_(1)))/(Bq)`
`E_(1)=(mE)/(m_(1))=((2m_(1)))/(m_(1))xx100KeV`
`=200keV" "[becausem=2m_(1)]`