Select the correct statement.

Options

A. In the decomposition of an oxide into oxygen and gaseous metal, entropy increased
B. Decomposition of an oxide is an endothermic change
C. To make `DeltaG^(@)` negative, temperature should be high enough so that `T DeltaS^(@) gt DeltaH^(@)`
D. All are correct statement

Answer

D

Explanation

As number of species on product side increases as compared to the reactant side, entropy increases. As we provide high temperature for decomposition of an oxide, it is an endothermic change and at the same time, it can also be said that the reaction becomes spontaneous i.e., `DeltaG` becomes negative (as `TDeltaS^(@)gtH^(@)`).