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In the synthesis of ammonia N(2)(g)+3H...

In the synthesis of ammonia
`N_(2)(g)+3H_(2)hArr2NH_(3)(g)`
If the quantity of `N_(2)` reacted is `700mL`, the quantity of `H_(2)` and `NH_(3)` would be

A

`300mLH_(2)` and `200mLNH_(3)`

B

`300mLH_(2)` and `300mLNH_(3)`

C

`300mLH_(2)` and `100mLNH_(3)`

D

`100mLH_(2)` and `200mLNH_(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`N_(2)(g)+3H_(2)(g)hArr2H_(3)(g)`
If the quantity of `N_(2)g` reacted is `100mL`
`:.` The quantity of `H_(2)(g)` is three times `300mL` and `NH_(3)` produced `=200mL`
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