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Given l//a=0.5 cm^(-1), R= 50 "ohm", N= ...

Given `l//a=0.5 cm^(-1), R= 50 "ohm", N= 1.0.` The equivalent conductance of the electrolytic cell is .

A

`10cm^(2)g//Omega` equiv

B

`20cm^(2)g//Omega` equiv

C

`300cm^(2)g//Omega` equiv

D

`100cm^(2)g//Omega` equiv

Text Solution

Verified by Experts

The correct Answer is:
A
Specific conductance
`(k)=1/(rho)=l/(Ra)=(0.5cm^(-1))/(50Omega)`
`lamda=kxx1000/N=0.5/50xx1000/1.0`
`=10cm^(2)g//Omega` equiv
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