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The equation of tangent of y^(2)=12x and...

The equation of tangent of `y^(2)=12x` and making an angle `(pi)/3` with X-axis is

A

`+-y-sqrt(3)x+sqrt(3)=0`

B

`+-y+sqrt(3)x+3=0`

C

`+-y-sqrt(3)x-sqrt(3)=0`

D

`+-y+sqrt(3)x-3=0`

Text Solution

Verified by Experts

The correct Answer is:
A
We have `y^(2)=12x`
`:.` Equation of tangent (in slope form ) is
`y=mx+a/m=sqrt(3)m+3/(sqrt(3))`
`y=sqrt(3)(x+1)`
`implies+-y-sqrt(3)x-sqrt(3)=0`
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-PRACTICE SET 08-PAPER 2 OBJECTIVE TYPE
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