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A ball is moving in a circular path of r...

A ball is moving in a circular path of radius 5m. If tangential acceleration at any instant is 10 `m//s^(2)` and the net acceleration makes an angle `30^(@)` with the centripetal acceleration, then the instantaneous speed is

A

`50sqrt(3)m//s`

B

`9.3m//s`

C

`6.6m//s`

D

`5.4m//s`

Text Solution

Verified by Experts

The correct Answer is:
B
From relation,
`tantheta=(a_(t))/(a_(c))=(a_(t))/(v^(2)//r)`
`impliesv^(2)=(a_(t)r)/(tantheta)`
`=(10xx5)/(tan30^(@))=50sqrt(3)`
`=50xx1.732=86.6`
`thereforev=sqrt(86.6)=9.3m//s`
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