When the road is dry and the coefficient of friction is `mu`, the maximum speed of a car in a circular path is 10 m/s. if the road becomes wet and `mu'=(mu)/(2)`, what is the maximum speed permitted?

Options

A. 5m/s
B. 10 m/s
C. `10sqrt(2)m//s`
D. `5sqrt(2)m//s`

Answer

D

Explanation

As, we Know `v=sqrt(mugr)`
When `mu` becomes `(mu)/(2)`, v becomes `(v)/(sqrt(2))`
i.e., `(10)/(sqrt(2))` or `(10sqrt(2))/(2)=5sqrt(2)m//s`.