The binding energy of deuteron is `2.2` MeV and that of `._(2)^(4)He` is `28` MeV. If two deuterons are fused to form one `._(2)^(4)He`, th `n` the energy released is

Options

A. 25.8 MeV
B. 23.6 MeV
C. 19.2 MeV
D. 30.2 MeV

Answer

B

Explanation

The reaction can be written as
`._(H)^(2)+._(1)H^(2)to._(2)He^(4)+`energy
The energy released in the reaction is the difference of binding energies of daughter and parent nuclei.
Hence, energy released
=binding energy of `._(2)He^(4)`
`-2xx`binding energy of `._(1)H^(2)`
`=28-2xx2.2=23.6`MeV