In an n-p-n transistor, the collector current is 10 mA. If 90% of the electrons emitted reach the collector, then the emitter current will be

Options

A. `l_(e)=1mA,l_(b)=11mA`
B. `l_(e)=11mA,l_(b)=1mA`
C. `l_(e)=-1mA,l_(b0=9mA`
D. `l_(e)=9mA,l_(b)=1mA`

Answer

B

Explanation

Given, `l_(c)=10mA`
also, 90% of `l_(e)=10`
`implies(90)/(100)l_(2)=10`
`thereforel_(e)=(100)/(9)mA=11mA`
Again, `l_(b)=l_(e)-l_(c)`
`=11.10=1mA`