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A very long magneti is placed vertically...

A very long magneti is placed vertically with one pole on the table. A neutral point was found at 20 cm from the pole. What is the pole strength if the vertical component of earth's field is `0.4xx10^(-4)Wb//m^(2)`?

A

16 A-m

B

8 A-m

C

4 A-m

D

none of the

Text Solution

Verified by Experts

The correct Answer is:
A

At neutral point,
`(mu_(0))/(4pi)xx(m)/(d^(2))=V`
or `10^(-7)xx(m)/((20//100)^(2))`
`=0.4xx10^(-4)`
or `m=(0.4xx10^(-4))/(25xx10^(-7))=16A//m`
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