A single slit of width a is illuminated by violet light of wavelength `400nm` and the width of the diffraction pattern is measured as y. When half of the slit width is covered and illuminated by yellow light of wavelength `600nm`, the width of the diffraction pattern is

Options

A. the patternn vanishes and the width is zero
B. `(y)/(3)`
C. `3y`
D. None of the above

Answer

C

Explanation

In single slit diffraction experiment,
width of central maxima.
`y=(2lamdaD)/(d)`
`therefore(y_(1))/(y_(2))=(lamda_(1))/(lamda_(2))xx(d_(2))/(d_(1))`
`=(400)/(600)xx(d//2)/(d)=(1)/(3)`
`y_(2)=3y`