The electron affinity values (in `kJ mol^(-1)` ) of three halogens, X, Y and Z are respectively -349, -333 and -325. Then X, Y and Z are respectively

Options

A. `F_(2),Cl_(2) and Br_(2)`
B. `Cl_(2),F_(2) and Br_(2)`
C. `Cl_(2),Br_(2) and F_(2)`
D. `Br_(2),Cl_(2) and F_(2)`

Answer

B

Explanation

The electron afffinity (in kJ/mol) value of the halogens are
`F_(2)=332.6,Cl_(2)=348.5,Br_(2)=324.7 and l_(2)=295.5`
`becauseCl_(2)` has highest electron affinity value.
`therefore`Correct order is
`X=Cl_(2),Y=F_(2),Z=Br_(2)`.